-8x^2=-26x

Solution for -8x^2=-26x equation:

-8x^2=-26x

We move all terms to the left:

-8x^2-(-26x)=0

We get rid of parentheses

-8x^2+26x=0

a = -8; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·(-8)·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*-8}=\frac{-52}{-16}
=3+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*-8}=\frac{0}{-16}
=0
$